
Attending a Las Vegas Raiders game is still one of the priciest trips for families in the NFL, but there is some relief for Raiders fans this season.
The Action Network, a sports media company focused on sports betting, released its analysis of over 500,000 ticket listings across all 32 NFL teams and added food, drink and parking prices to calculate stadium cost for a family of four.
Allegiant Stadium ranked sixth in this year’s study with a total game-day cost of 1,805.99, more than $175 cheaper than last year’s figure after the stadium ranked as the third-most expensive in the league. The NFL average is $1,474.55 for the 2026 season, which puts Raiders game-day expenses for a family of four over $330 higher than the league average.
The study’s stadium cost accounts for four general admission tickets, two beers, two soft drinks, four hot dogs and parking. Cost movement largely hinges on ticket prices, which are reflective of a team performance and fan demand.
The decline in cost at Allegiant Stadium comes with ticket prices falling after the Raiders finished 3-14 last season. The price total for four tickets dropped $210.80 from last year, the second sharpest decline behind only the Pittsburgh Steelers, who saw a $347.12 decrease in their average family-of-four price.
However, the cost of doing business in a new stadium has kept prices high in Las Vegas.
Overall, the average cost for four tickets to a Raiders game is $1,644.36, ranking 11th in this year’s study. Two beers, costing $31, and four hot dogs at $42.44 both are the second-most expensive prices in their categories. Parking at Allegiant Stadium ranks fifth with a cost of $75, while the cost of two soft drink at $13.19 ties for 10th.
The Buffalo Bills’ new home at Highmark Stadium ranked as the most expensive family-of-four cost at $2,193.95. The family-of-four ticket prices climbed nearly $350, while parking at the new stadium costs $132, the highest parking cost in the NFL.
Contact Trevor Squire at tsquire@reviewjournal.com. Follow him at @trevordsquire on X.